Carnen enters a painting contest. the contest rules say that all paintings must be rectangular with an area no graether than 3003.04cm2carmens painting is 16 cm wide. whar is the grather length the painting can have and still have an area within the contest rules?

This problem requires the knowledge of the area of a rectangle.
The area of any rectangle is Area=Length•Width.
Since the maximum area is 3003.04 cm² and the width is 16 cm, you the area and length into this equation.
3003.04=16•Width
To solve for your width you must divide 3003.04 by 16.
3003.04÷16=187.69
So the greatest possible width of Carmen's painting is 187.69.

The vertex of the quadratic function is (1.5, -.75)