Mathematics, 02.10.2019 02:30 maryanapritchak1829
Indefinite integral of x^3 sqrt(x^2 + 1 dx? with steps
Answers: 1
![\large\begin{array}{l} \texttt{Last, substitute back for }\mathtt{u=\sqrt{x^2+1}}\texttt{ and then}\\\texttt{you get}\\\\ \mathtt{=\dfrac{\big(\!\sqrt{x^2+1}\big)^5}{5}-\dfrac{\big(\!\sqrt{x^2+1}\big)^3}{3}+C}\\\\ \mathtt{=\dfrac{\big[(x^2+1)^{1/2}\big]^5}{5}-\dfrac{\big[(x^2+1)^{1/2}\big]^3}{3}+C}\\\\ \mathtt{=\dfrac{(x^2+1)^{5/2}}{5}-\dfrac{(x^2+1)^{3/2}}{3}+C} \end{array}](/tpl/images/0281/7254/784b2.png)
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Indefinite integral of x^3 sqrt(x^2 + 1 dx? with steps...
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