Calculate the area of triangle abc with altitude cd, given a(−7, −1), b(−1, 5), c(0, 0), and d(−3, 3). (6 points) 9 square units 18 square units 18.5 square units 21 square units

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

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step-by-step explanation: