I. let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2
+ 1. compute the following:

1. f(g(-1))
2. f o h(3)
3. g(f(-5))
4. h(f(x))
5. f(f(x)) 6
. h o g(x)

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

34

step-by-step explanation: