Given a= 25 b= 43 and c=17, solve triangle abc. round to the nearest hundredth.

It is given that , In ΔABC , in which, ∠A=25°, ∠B=43°,

Length of side c= 17 units

As, angle sum property of triangle says that

∠A +∠B +∠C=180°

25°+43°+ ∠C=180°

∠C=180° -68°

∠C=112°

Using Sine Rule

So, Side opposite to angle A=a=7.75 units

Side opposite to angle B=b=12.50 units

And , ∠C=112°

a - base

b - exponent

so,