The figure is a sphere with a cone within it. to the nearest whole number, what is the approximate volume of the shaded part of this figure? use 3.14 for pi. drag the correct value to the box.
13
113
503
29
92

92 m³

First we are going to find the volumes of the sphere and cone separately; then, we'll subtract the volume of the cone from the volume of the sphere.

Volume of the sphere:

where

is the volume of the sphere

is the radius

We can infer from our picture that r = 3 m, so let's replace the value

Volume of the cone:

where

is the volume of the cone

is the radius  

is the height

We can infer from our picture that r = 2 m and h = 5 m, so let's replace the values

Volume of the shaded area = volume of the sphere - volume of the cone

Volume of the shaded area =

And rounded to the nearest integer:

Volume of the shaded area =

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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