You have 8 batteries sitting on your desk, 3 of which are dead. your calculator requires 2 good batteries to function. if you select 2 batteries at random, what is the probability your calculator will not function

Let x be the case that calculator Does function. x' means it will not function.
Then P(x') = 1 - P(x)

Its easier to find P(x) since it requires that both batteries are good.
There are 3 dead batteries and 5 good ones.
P(x) can be found by dividing at the combinations which gives 2 good batteries by total combinations.



Therefore there is a 9/14 chance the calculator will not function.