Suppose an investment of $6,600 doubles in value every 8 years. how much is the investment worth after 40 years? $66,000 $528,000 $105,600 $211,200

Answer

Find out the  how much is the investment worth after 40 years .

To prove

As given

Suppose an investment of $6,600 doubles in value every 8 years.

Thus

$6600 is the intial investment.

$6600 doubles i.e becomes $13200 in 8 years.

$13200 doubles i.e becomes $26400 in 16 years.

$26400 doubles i.e becomes $52800 in 24 years.

$52800 doubles i.e becomes $105600 in 32 years.

$105600 doubles i.e becomes $211200 in 40 years.

Therefore the is $211200 is  the investment worth after 40 years.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

87%

step-by-step explanation:

apex answer