What is the equation of the line that is perpendicular to f(x) and passes through the point (4, –6)? a.4x + 3y = –2
b. 3x + 4y = –12
c.4x – 3y = 34
d.3x – 4y = 36

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16

answer: i think its b