a piecewise-defined function is graphed below. (see image)

which of the following statements are true for this function? select all that apply. there's more than one

the function is discontinuous at x = -1
the function is discontinuous at x = 1.
the value of the function is never negative.
x = 1 is not in the domain of the function.
the value of the function at x = -1 is 0.
the value of the function at x = 1 is 0.

The function is discontinuous at x = 1.

The value of the function is never negative.

The value of the function at x = -1 is 0

Step-by-step explanation:

Given is a graph of   a function first a straight line, followed by a semi circle centred at the origin and another piece of straight line not connected to the other graph.

We can see that the funciton is discontinuous at x=1 since

right limit = 1 and left limit =0

x=1 is in the domain .

f(-1) =0 is right

But f(1) =0 is incorrect

Thus correct options are

The function is discontinuous at x = 1.

The value of the function is never negative.

The value of the function at x = -1 is 0

The function is discontinuous at x = 1.

The value of the function is never negative.

The value of the function at x = -1 is 0Step-by-step explanation:

answer: no, but if it does it's a obvious pattern.

step-by-step explanation:

2160ft3

step-by-step explanation: