2x+12≥6
whats the solution?
a. x≥-3
b. x≤ 3
c. x≤ -3
d. x≥3

2x+12≥6
Subtract 12 from both sides
2x≥-6
Divide 2 on both sides while flipping the inequality
Final x≤-3

D if tou change x with 3 or any number bigger than 3 then the answer would be that your problem is biggeror equal to 6 in this case bigger

Img()3! : $3! : ! ? : $ sugz

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.