In triangle abc ab=2cm ac=6cm and bc=2root7cm
a) use the cosine rule to show
the circle with centre a and radius 2cm intersects ac at point d
b)calculate the length in cm of the arc bd

c) calculate the area in cm^2 of the shaded region bcd

I drew a diagram and labeled some points. is the centre of the circle and D, E and F are points where the sides of the triangle are tangent to the circle. Thus angles CAB, PDB and BEP are right angles. Suppose the radius of the circle is r and the side length of CA is s. By the symmetry of the diagram E is the midpoint of BC. Notice also that the length of AD is r.

I used Pythagoras Theorem 3 times. Once for the triangle ABC to find the length of BC and hence BE in terms of s. A second for triangle BEP to find the length of BP, and a third time for triangle BPD to write an equation involving s and r. Solve for r.

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation: