Factor 16x^2 + 16x + 4 completely
a. (16x + 4)(x + 1)
b. (4x + 2)(4x - 2)
c. 4(2x...
Mathematics, 26.11.2019 22:31 jumana3
Factor 16x^2 + 16x + 4 completely
a. (16x + 4)(x + 1)
b. (4x + 2)(4x - 2)
c. 4(2x + 1)^2
Answers: 2
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