List the sides of each triangle in order from shortest to longest
{pictures are attached below}
1. in δpqr, the measure of angle p = 55, the measure of angle q = 82 and the measure of angle r = 43. list the sides of the triangle in order from shortest to longest (no picture was provided).
2. in δmns, mn = 7, ns = 5, and ms = 9. list the angles of the triangle in order from smallest to largest (no picture was provided).
3. two sides of a triangle have side lengths 8 units and 17 units. describe the lengths (x) that are possible for the third side (no picture was provided).
***i will be awarding brainliest answer and 30 points***

For 1:

PQ < QR < PR

For 2:

NS < MN < MS

For 3:

17-8 < x < 17+8

Step-by-step explanation:

The side opposite to the smallest angle will be the shortest.

So, from the image ∠R is the smallest, fso the side opposite to it, which is PQ will be the shortest.

The largest side will be the side whcih is opposite to ∠Q which is PR.

So the order of sides from smallest to largest is:

PQ < QR < PR

Length of MN = 7 units

Length of MS = 9 units

Length of NS = 5 units

The order of the sides from smallest to largest is:

NS < MN < MS

We are given two sides of the triangle which sre 17 units and 8 units and third side is taken 'x'.

So the third side 'x' will lie between the difference of the two sides and the sum of the two sides.

So, the length of 'x' will be:

17-8 < x < 17+8

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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