2. solve the following system of equations using substitution.
2x+2y=38
y=x+3

a.(8,11)
b.(4,7)
c.(35/4, 47/4)
,-7)

First, make sure you convert both equations into standard form. Your two equations would be 2x+2y=38 and -x+y=3. Then multiply the bottom by 2. So your new equations would be 2x+2y=38 and -2x+2y=6. The x would cancel out and you would continue solving for y. y would equal 11 and then you would plug it back into an original equation. When you plug and solve for x, you would get x=8. So your answer would be (8,11)

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