In the figure, j∥k and m∠2 = 117°. what is the m∠3 ? enter your answer in the box.

measure of the ∠3 is 63°.

Step-by-step explanation:

Given: j is parallel to k and t is the transversal and measure ∠2=117°.

To find: The measure of ∠3

Solution: It is given that the measure of ∠2 is 117° and from the figure, it can be seen that the ∠2 and ∠3 forms a linear pair, thus

⇒∠2 +∠3=180°

⇒117°+∠3=180°

⇒∠3=180-117

⇒∠3=63°

Therefore, the measure of the ∠3 is 63°.

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3