The length of a rectangle is 6in. more than than its width .its area is 50 sq. in find the width of the

L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=
we got
a=1
b=6
c=-50

W=
W=
W=
W=
W=

W= or W=
aprox
W=-10.6811 or W=4.68115
can't be negative width

width=4.68115 or -3√59

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