On a scale drawing of a museum, two water fountains are 10 inches apart. the actual distance between them is 400 feet. on the same drawing, the distance between two exhibits is 3.125 inches. what is the actual distance between these two exhibits? 13 feet 125 feet 313 feet 425 feet

The actual distance between these two exhibits = 125 feet.

Step-by-step explanation: Two water fountains are 10 inches apart on a scale of drawing museum

The actual distance between them is 400 feet.

On the same drawing, the distance between two exhibits is 3.125 inches.

To Find : What is the actual distance between these two exhibits?

Since Two water fountains are 10 inches apart on a scale of drawing museum and The actual distance between them is 400 feet.

⇒ 10 inches = 400 feet

So, 1 inch = 400/10

⇒1 inch = 40 feet

Since we are given that  the distance between two exhibits is 3.125 inches.

So , the actual distance between two exhibits (i.e.in feet ) (Using 1 inch = 40 feet)

= 3.215*40

= 125 feet

Thus , The actual distance between these two exhibits = 125 feet.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w