For the given statement pn, write the statements p1, pk, and pk+1.
2 + 4 + 6 + . . + 2n = n(n+1)

=  2

= k(k+1)

= (k+1)(k+2)

Step-by-step explanation:

We are given the statement,

as 2 + 4 + 6 + . . . + 2n = n(n+1)

That is,

as 2 + 4 + 6 + . . . + 2n =

So, we have,

= = 2

= = 2 + 4 + 6 + . . . + 2k = k(k+1)

= = 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)

Thus, we get,

=  2

= k(k+1)

= (k+1)(k+2)

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph