6x^2 + 3x - 1 =0 use the quadratic formula to solve for x

The answer is :x=3±√3312x=3±3312x≈0.72871355,−0.22871355
Use the quadratic formula to find the solutions.−b±√b2−4(ac)2a-⁢b±b2-4⁢a⁢c2⁢aSubstitute the values a=6a=6, b=−3b=-3, and c=−1c=-1 into the quadratic formula and solve for xx.3±√(−3)2−4⋅(6⋅−1)2⋅63±-32-4⋅6⋅-12⋅6Simplify.Tap for less steps...Simplify the numerator.Tap for less steps...Raise −3-3 to the power of 22 to get 99.x=3±√9−4⋅(6⋅−1)2⋅6x=3±9-4⋅6⋅-12⋅6Multiply 66 by −1-1 to get −6-6.x=3±√9−4⋅−62⋅6x=3±9-4⋅-62⋅6Multiply −4-4 by −6-6 to get 2424.x=3±√9+242⋅6x=3±9+242⋅6Add 99 and 2424 to get 3333.x=3±√332⋅6x=3±332⋅6Simplify the denominator.Tap for less steps...Rewrite.x=3±√332⋅6x=3±332⋅6Multiply 22 by 66 to get 1212.x=3±√3312x=3±3312The result can be shown in both exact and approximate form.x=3±√3312x=3±3312x≈0.72871355,−0.22871355

The coordinates of point a right now is (-3,-1) you have to multiply these coordinates by a factor of 2 to get (-6,-2)

How many groups are there?