Mathematics, 10.11.2019 13:31 cherry12345627

Which polynomial is factored completely?

121x^2+36y^2

(4x+4)(x+1)

2x(x^2-4)

3x^4-15n^3+12n^2

Answers: 3

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Answers

Answer from: jaylanmahone223

Complete factored: (4x+4)(x+1) and 2x(x²-4)

Step-by-step explanation:

We have to check each option one by one

Option 1: 121x^2+36y^2

It is sum of two perfect square, As we know sum of two perfect square can't be factored. It is prime equation.

False

Option 2: (4x+4)(x+1)

Here we have two factor (4x+4) and (x+1). In both factor degree of x is 1. It is complete factor form.

Complete factor: 4(x+1)(x+1)

True

Option 3: 2x(x^2-4)

Here we have two factor 4x and x²-4. For second factor it is further factor. Because it is difference of square. Factor of x²-4 = (x+2)(x-2)

Complete Factor: 2x(x+2)(x-2)[/tex]

True

Option 4: 3x^4-15n^3+12n^2

Here variable are not same. So, it can't be factor.

False

Answer from: eggemotions

The completely factored polynomials are $\boxed{2x\left( {{x^2} - 4} \right)}$ and $\boxed{\left( {4x + 4} \right)\left( {x + 1} \right)}$ . Option (b) and option (c) are correct.

Further Explanation:

Given:

The options are as follows,

(a). $121{x^2} + 36{y^2}$

(b). $\left( {4x + 4} \right)\left( {x + 1} \right)$

(c). $3{x^4} - 15{n^3} + 12{n^2}$

(d). $3{x^4} - 15{n^3} + 12{n^2}$

Calculation:

In option (a)

The expression $121{x^2} + 36{y^2}$ is not in the factored form. option (a) is not correct.

In option (b)

The expression $\left( {4x + 4} \right)\left( {x + 1} \right)$ is in the factored form.

${\text{Factored}} = 4{\left( {x + 1} \right)^2}$

Option (b) is correct.

In option (c)

The expression $2x\left( {{x^2} - 4} \right)$ is in the factored form.

$\begin{aligned}{\text{Factored}} &= 2x\left( {{x^2} - 4} \right)\\&= 2x\left( {x + 2} \right)\left( {x - 2} \right)\\\end{aligned}$

Option (c) is correct.

In option (d)

The expression $3{x^4} - 15{n^3} + 12{n^2}$ is not in the factored form.

Option (d) is not correct.

The completely factored polynomials are $\boxed{2x\left( {{x^2} - 4} \right)}$ and $\boxed{\left( {4x + 4} \right)\left( {x + 1} \right)}.$ Option (b) and option (c) are correct.

Learn more:

Learn more about unit conversion link Learn more about non-collinear link Learn more aboutbinomial and trinomial link

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponents and Powers

Keywords: solution, factored, completely, polynomial, factorized form, expression, difference of cubes, exponents, power, equation, power rule, exponent rule.

Answer from: Quest

the expected value of the random variable : 0, 1 and 2

step-by-step explanation:

Answer from: Quest

2.83941151 would be the answer you're looking for! : )

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Which polynomial is factored completely?

121x^2+36y^2

(4x+4)(x+1)

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