Given two lines: 5x + 2y = 6, and 3x - ay = 4
which value of a makes given lines parallel to each other?

1/ Let's isolated y for both equations

5x + 2y = 6 becomes y = -5/2x +3

3x - ay = 4  becomes y = 3/ax - 4/a


2/ The slope of each lines is m, which is the coefficient in front of the x (here -5/2x & 3/ax)


3/ So we just need to solve for these 2 coefficient (m) being equal in order for the 2 lines to be parallel.

meaning we want to find a for : -5/2 x = 3/a x

4/ Let's solve then:

cancel out the two x on each side

-5/2 = 3/a

isolate a:

a = - 6/5

You move the constant to the right side and change its sign to be 9z= -6 -8. that’s the first step.the second step would be calculate the difference of -8-6 to get -14. you equation should now be 9z=-14the last step is to divide both sides by 9 to get z=-14/9hope this