On a road, a bike sign in the shape of an isosceles trapezoid is to be painted. the sign and its dimensions are shown below. what is the area of the sign?

a right trapezoid is shown with a height labeled 6 feet and one of the bases labeled as 7 feet, and the other base is labeled as 5 feet.

30 square feet
36 square feet
48 square feet
54 square feet

Answer for question #2).   The answer is:  [B]:  " 36 square feet" .

Explanation:

Area of trapezoid: A = (1/2) (base 1 + base 2) * h ; 

or; write as:  A = (1/2) * (b₁ + b₂) * h ; 

in which:  A = area of trapezoid;
                b₁ = length of one of the bases;
                b₂ = length of the "other" base (not already used for "b₁") ;
                h = height;

Given:  h = 6 ft. ;
             b₁ = 7 ft. ;
             b₂ = 5 ft. ;

Find the area of the trapezoid:

 A = 1/2 * (7 ft + 5 ft) * 6 ft. ;

 A = 1/2 * (12 ft) * 6 ft. ;

 A = 36 ft² ; which is answer choice: [B].

Ithink it should be 55.