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Mathematics, 23.10.2019 16:00 j015

What is the initial value of the equation shown?

y = βˆ’2x βˆ’ 5

βˆ’5

βˆ’2

2

5

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Answers: 1

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You know the right answer?
What is the initial value of the equation shown?

y = βˆ’2x βˆ’ 5

βˆ’5

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