A50-ft cable is stretched from the top of an antenna to an anchor point on the ground 15ft. from the base of the antenna . how tall is the antenna?

I do not believe the previous answer is correct. This is an a^2+b^2=c^2 problem. The 50 foot cable is the hypotnuse (c) and 15 foot gap is one of the sides (a). So take 15 and square it. Then square 50. You then should have 15^2+b^2=50^2. Subtract 15^2 to the right side, then square root the answer to get b, the height of the antenna.

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