At 6: 00 a. m., there were 800,000 gallons of water remaining in a reservoir. after 8 hours of irrigation, there were 100,000 gallons of water remaining. write a linear equation that describes the number of gallons of water remaining as a function of the time the field had been irrigated.

WR(t) = 800000 - 87500t

Explanation:

t is the time in hours.

WR(t) is the Water Remaining as a function of the time, in gallons.

WR(t) = 800000 - 87500t

Explanation:

t is the time in hours.

WR(t) is the Water Remaining as a function of the time, in gallons.

WR(t) = 800000 - 87500t

Explanation:

t is the time in hours.

WR(t) is the Water Remaining as a function of the time, in gallons.

The problem states the initial amount of water in the reservoir is 800000 gallons.

Then we need to find the amount of water spent each hour. For this we know that after 8 hours, 100000 gallons remain.

In other words:

800000 - 100000 = 700000 gallons have been spent in 8 hours.

Which gives a ratio of 700000 / 8 = 87500 gallons per hour.

Writing all together, the linear equation is built by taking the initial amount of water and subtracting the ratio of water spent, multiplied for the time variable:

WR(t) = 800000 - 87500t

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,

inverse operation of addition