−3a2 − b3 + 3c2 − 2b3 if a = 2, b = −1, and c = 3.

((−3)(2))(2)−(−1)(3)+(3)(3)(2)−(2)(−1)(3)

=(−6)(2)−(−1)(3)+(3)(3)(2)−(2)(−1)(3)

=−12−(−1)(3)+(3)(3)(2)−(2)(−1)(3)=−12−(−3)+(3)(3)(2)−(2)(−1)(3)

=−9+(3)(3)(2)−(2)(−1)(3)

=−9+(9)(2)−(2)(−1)(3)

=−9+18−(2)(−1)(3)

=9−(2)(−1)(3)

=9−(−2)(3)

=9−(−6)

=15

False because how does that work?