For circle o, m cd=125 and m
in the figure< (aob, abo, boa)
and < (bco, obc, boc) have measures equal to 35°

In the figure, ABO and BCO equal to 35

Step-by-step explanation:

<ABO and <BCO equal to 35

Step-by-step explanation:

Measure of arc AD = 180-measure of arc CD= 180-125 =55

m<AOB= 55 ( measure of central angle is equal to intercepted arc)

<OAB= 90 degrees (Tangent makes an angle of 90 degrees with the radius)

In triangle AOB ,

< AB0 = 180-(90+55)= 35 degrees( angle sum property of triangle)

In triange BOC ,< BOC=125 ,

m<, BCO=35 degrees