Find the area of the image below: figure abcde is shown. a is at 6, 0. b is at negative 4, 5. c is at 2, 5. d is at 2, 9. e is at 6, 9. 41 square units 44 square units 52 square units 56 square units

The area of image is: 41 square units

The area of the image is equal to:

Area of square CDEF+Area of right angled triangle ΔBFA

In square CDEF we have:

The lengths of the side of the square= 4 units

Hence, the area of square is: side²

i.e. Area of square= 4²=16 square units

Also, in ΔBFA we have:

The base of the triangle is: BF=CB+CF=6+4= 10 units

Also, height of the triangle is: FA= 5 units

Hence, we have area of ΔBFA as:

Area= 1/2×BF×FA

i.e.

Area= 1/2×10×5

i.e.

Area= 25 square units

Hence, the area of image is: 16+25

i.e.

Area of image= 41 square units

where is the rest of the

step-by-step explanation:

eve and marks ratios are equivalent

step-by-step explanation: