Given the equation −4square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.

a.) x = 0, solution is not extraneous
b.) x = 0, solution is extraneous
c.) x = 12, solution is not extraneous
d.) x = 12, solution is extraneous

D.) x = 12, solution is extraneous

Step-by-step explanation:

We are given a equation

⇒    

 on squaring both sides, we get

           x-3=9

    ⇒  x=12

     Putting x=12 in original equation gives

⇒            -4×3=12

which is not true

Hence, correct option is:

D.) x = 12solution is extraneous