If f(x) = x + 1 and g(x) = 2x – 7, which expression is equivalent to [f o g](3)?
a. (3 + 1)(2(3) –7)
b. 2(3)2 – 6
c. 2(3 + 1) – 7
d. (2(3) – 7) + 1

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.