Anna is weighing packages she is going to mail. they weigh 15.6 ounces, 13.25 ounces, 8.6 ounces, 9.75 ounces, and 18.23 ounces. estimate the total weight of the five packages.

Molly is an insurance agent. She is mailing packages filled with marketing items to a few of her clients. The items she is including are pens that weigh x ounces, notepads that weigh y ounces, and magnets that weigh z ounces: A package filled with 3 pens, 2 notepads, and 1 magnet weighs 8 ounces. A package filled with 2 pens, 1 notepad, and 2 magnets weighs 3.9 ounces. A package filled with 4 pens and 3 magnets weighs 4 ounces. Which matrix equation can be solved to find the weight of each item

Step-by-step explanation:

Molly is an insurance agent. She is mailing packages filled with marketing items to a few of her clients. The items she is including are pens that weigh x ounces, notepads that weigh y ounces, and magnets that weigh z ounces: A package filled with 3 pens, 2 notepads, and 1 magnet weighs 8 ounces. A package filled with 2 pens, 1 notepad, and 2 magnets weighs 3.9 ounces. A package filled with 4 pens and 3 magnets weighs 4 ounces. Which matrix equation can be solved to find the weight of each item

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.