Your car's back window is in the shape of a trapezoid with the dimensions shown. the 1616-inch window wiper cleans a part of the window in a semicircular pattern. what is the approximate area of the window that is not cleaned by the wiper?

Semicircle area = circle area / 2 = (pi*r^2)/2 16 in is the radius. Let's call the area of this semicircle s. 3.14*16^2=s

Trapezoid area = ((base 1 + base 2) / 2) * h Here, base 1 is 44 and base 2 is 36. The height (h) is 20. Let's call this trapezoid's area t. (44+36)/2 *20 = t

We can remove the area of the semicircle (that created by the windshield wiper) by subtracting it from the area of the trapezoid. t - s = uncleaned area [(44+36)/2 * 20] - [3.14 * 16^2] = uncleaned area

25% increaseplus i think decrease i only know increase: ((

If gravity is one third on mars then weight also one third on mars