How do i get the answer for this limit limit x to 0 (4^2x-1)
without using direct substitution my work so far is limit x to 0= (4^2x-1) = (4^2x/4^-1) is it correct?

Which statements are true? check all that apply. the line x = 0 is perpendicular to the line y = –3. all lines that are parallel to the y-axis are vertical lines. all lines that are perpendicular to the x-axis have a slope of 0. the equation of the line parallel to the x-axis that passes through the point (2, –6) is x = 2. the equation of the line perpendicular to the y-axis that passes through the point (–5, 1) is y = 1.