The given line segment has a midpoint at (3, 1).

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the given line segment has a midpoint at (3, 1).
what is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?

a. y =1/3 x
b. y =1/3 x – 2
c. y = 3x
d. y = 3x − 8

Let A(2,4) & B(4,-2)

The slope of AB = m =

Now we know the slope of a line perpendicular is -1/m

So slope of perpendicular line to AB shall be m =

Hence the equation of line shall be

Now this line passes through (3,1)

Substituting in the equation we get

1=1+c

c=0

Hence the equation of the line perpendicular to AB is

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