If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
the figure must be an isosceles trapezoid because it has 2 congruent base angles.
the figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.
the figure must be a rhombus because it has exactly 2 pairs of congruent angles.
the figure must be a square because the diagonals of a square bisect the right angles.
i'm thinking rhombus, is that right?

A quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors.

A trapezoid has diagonals which do not bisect each other as well as they do not bisect the angle.

A rectangle has 2 lines of symmetry but its diagonals even though bisect each other do not bisect the angles.

A square's diagonals do bisect each other as well as the angles, but a square has 4 lines of symmetry,

So a rhombus whose diagonals bisect each other as well as the angles should be the quadrilateral.

So a quadrilateral which has exactly 2 lines of symmetry, and both are angle bisectors, is the rhombus.

Third option or Option C) is the right answer.

correct answer:

b.(19,-2)

what graph

step-by-step explanation: