what is the solution to
x^2+3x+25=0

show all steps

X^2 + 3x + 25 = 0

Since the quadratic equation is not factorable

Then use the quadratic formula to solve it

X = [- b + sqrt(b^2 – 4ac)] / 2a

and

X = [- b - sqrt(b^2 – 4ac) ]/ 2a

X = [- 3 + sqrt(3^2 – 4(1)(25))] / 2(1)

X = [- 3 + sqrt( - 91 ) ]/ 2

X = -3/2 + sqrt( 91)i/2

So the other solution

X =  -3/2 - sqrt( 91)i/2

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x