The isosceles trapezoid is part of an isosceles triangle with a 34 degree vertex angle. what is the measure of an acute base angle of the trapezoid?

For the answer to the question above asking what is the measure of an acute base angle of the trapezoid?
n acute base angle of the trapezoid would be the same as the triangle. 

subtract 34º from 180º, then divide by 2. 

(180 - 34)/2 = 73º 
I hope my answer helped you.

The answer is: y would equal 3 because if you simplify the equation then it would be y= 3x+9 and if you divide 3x and 9 by 3 it would equal 3. y= 3