Write an equation for the linr that is parallel to the given lin and passes through the given point. y=5x+10; (2,14)
y=1/5x+4
y=-1/5x-4
y=5x=68
y=5x+4

Y = 5x + 10...slope here is 5. A parallel line will have the same slope.

y = mx + b
slope(m) = 5
(2,14)...x = 2 and y = 14
now we sub and find b, the y int
14 = 5(2) + b
14 = 10 + b
14 - 10 = b
4 = b

so ur parallel equation is : y = 5x + 4