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Mathematics, 01.09.2019 02:50 katdoesart65091

Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.
f(x) = βˆ’1/2 times (x βˆ’ 6)^2 + 3/2
f(x) = 1/2 times (x βˆ’ 6)^2 + 3/2
f(x) = βˆ’1/2 times (x + 3/2)^2 + 6
f(x) = 1/2 times (x + 3/2)^2 + 6

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Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.
f(x) = βˆ’1...
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