The cost in dollars to produce x cups of lemonade is represented by the function c(x) = 10 + 0.20x. the revenue in dollars earned by selling x cups of lemonade is represented by the function r(x) = 0.50x. what is the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost?

Hello there.

The cost in dollars to produce x cups of lemonade is represented by the function C(x) = 10 + 0.20x. The revenue in dollars earned by selling x cups of lemonade is represented by the function R(x) = 0.50x. What is the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost?

Answer 34

For the answer to the question above,
revenue to exceed cost: R(x) > C(x)
0.50x > 10 + 0.20x
0.50x - 0.20x > 10
0.30x > 10
x > 10/0.30
x > 33.333

Therefore the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost is 34.
I hope this helps