If cos θ = square root 2 over 2 and 3 pi over 2 < θ < 2π, what are the values of sin θ and tan θ?

For the answer to the question above, If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? 

If 3 pi over 2 < Θ < 2π Then the signs of sinx and tanx are both negative. 

cos(x) = sqrt(2)/2. So sin(x) = -sqrt(2)/2 and tan(x) = -1. 

sin Θ = square root 2 over 2; tan Θ = −1 

sin Θ = negative square root 2 over 2; tan Θ = 1 

sin Θ = square root 2 over 2; tan Θ = negative square root 2 

sin Θ = negative square root 2 over 2; tan Θ = −1

Deja qué x = longitud6(x) = 48cm^2divide por 6: x = 8la área de longitud es 8 cm.