Suppose that 50 identical batteries are being tested. after 8 hours of continuous use, assume that a given battery is still operating with a probability of 0.70 and has failed with a probability of 0.30. what is the probability that between 25 and 30 batteries (inclusive) will last at least 8 hours

Given: Bernoulli trials, (population) success rate = p = 0.7 (constant throughout trials) Assume independence of the 50 batteries use binomial distribution with parameters (n,p)=(50,0.7) P(X\in {25,26,27,28,29,30}) =0.001436+0.003223+0.006684+0.012811+0.022677 =0.037039

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step-by-step explanation:

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step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2