Line jk passes through points j(–3, 11) and k(1, –3). what is the equation of line jk in standard form?

a. 7x + 2y = –1
b. 7x + 2y = 1
c. 14x + 4y = –1
d. 14x + 4y = 1

If the Line JK passes through points J(–3, 11) and K(1, –3), so the the equation of line JK in standard form is b. 7x + 2y = 1

proof:
for J(–3, 11),  7(-3) +2(11)=-21+22=1
for K(1, –3),  7(1) +2(-3)= 7-6=1
 

The answer is c because you turn 17.5% into a decimal which gives you .175 then you times that by $361.35 which gives you 63.23625 but then you round that which gives you 63.24. then you at 63.24 pulse 361.35 and you round it which gives you $425