Aripe pear falls from a tree and lands on the ground. as it hit the ground, the pear had a speed of 28 feet per second. approximately how far up in the tree was the pear before it fell? use the formula below, and assume that the acceleration due to gravity is 32 feet per second squared:

The potential energy is converted into kinetic energy.

 Therefore, for conservation of energy we have:

 mgh = (1/2) m * v ^ 2

 From here we clear the speed:

 v = root (2 * g * h)

 The height will then be:

 h = v ^ 2 / (2 * g)

 Substituting the values:

 h = (34) ^ 2 / (2 * (32))

 h = 18.0625 feet

  The pear before it fell was 18.0625 feet up in the tree.

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day

they would have to work 32 hours.