How to write y = 5/6x + 9 in standard form using integers

First... we need to get rid of fraction the fraction is 5/6 ...so we need to multiply both side by 6 

6y = (6)(5/6)x + (6)(6) 

from that ...we get 

6y = 5x + 36 

so according to the "Standard Form" formula... we need to rearrange 
Ax + By = C 

we subtract 5x to the left 

(-5x) + 6y = 36 

Standard form is
ax+by=c
a,b,c are integers and a is normally positive
get rid of all fractions

y=5/6x+9
times 6 both sides
6y=5x+54
minus 5x both sides
-5x+6y=54
times -1 both sides
5x-6y=-54