Algebra: explain in words how to write an equation that is part one: parallel and then also part two: perpendicular to the equation y=2/3x-4 passing through the point (-2,-5). write the answer in standard form.

A line that is parallel has the same slop where a line that is perpendicular has a slop that is negative and reciprocal.

so for the parallel one you don't need to worry about the slop because it will be 2/3x. But yous the point slope equation form

y-y1=m(x-x1)

y+5=2/3(x+2)

y+5=2/3x+ 4/3

y=2/3x-11/3

-2/3x+y=-11/3

multiple by -1 so A inst negative

2/3-y=11/3

For a line that is perpendicular you just need to flip the original 2/3x slope and make it negative.

y+5=-3/2(x+2)

y+5=-3/2x-3

y=-3/2x-8

3/2x+y=-8

Answer\ __o_o__/ lil i don’t kniw