Aboy throws a baseball across a field. the ball reaches its maximum height, 18 meters, after 1 second. after approximately 2.3 seconds, the ball lands on the ground. the ball’s motion can be modeled using the function f(x) = –10x2 + 20x + 8. what is the height of the ball 1.5 seconds after it is thrown?
11.7 meters
13.8 meters
15.5 meters
17.5 meters

height is 15.5 meters

Step-by-step explanation:

A boy throws a baseball across a field. The ball reaches its maximum height, 18 meters, after 1 second. After approximately 2.3 seconds, the ball lands on the ground. The ball’s motion can be modeled using the function f(x) = –10x2 + 20x + 8

To find the  height of the ball 1.5 seconds after it is thrown

Plug in 1.5 for x and find out the height

f(x) = –10x^2 + 20x + 8

f (1.5) = –10(1.5)^2 + 20(1.5) + 8= 15.5

So the height is 15.5 meters

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)