Atank of water holding 528 kl of water begain to empty at a rate of 10 kl/min at the same time a another tank whitch is empty begins to fill at a rate of 14kl/min let k repreasens the number of kiloliters of water and let t repreasent time in min the system models the solution
how long will it take for each tank to have the same amount of water , and how much water will that be
it will take __minitutes for both tanks to hold equal amounts of water . they will each hold kiloliters.

This is a system of equations.  The first equation represents the tank being emptied and the second equation represents the tank being filled:

k = -10t + 528
k = 14t

To solve this system of equations, we will use substitution. The second equation says that k is equal to 14t, so we can substitute 14t for k in the first equation.

14t = -10t + 528
24t = 528
t = 22

Now that we have t, we can use it to find k by plugging it in to the second equation:

k = 14(22)
k = 308

So, it will take 22 minutes for both tanks to hold equal amounts of water. They will each hold 308 kiloliters.

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