Mathematics, 04.11.2019 13:31 angeleyes4u610p6np54

One location of the smart growing preschool has 22 children in the primary class and 18 children in the toddler class. the other location has 30 children in the primary class and 15 children in the toddler class. the revenue at the first location is $24,250, and the revenue at the second location is $27,150. how much do parents pay for a primary child and a toddler child every month?

a.$595 for a primary child and $620 for a toddler child.
b.989 for a primary child and $1,558 for a toddler child.
c.1,353 for a primary child and $307 for a toddler child.

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Answer from: sloane50

Parents pay for primary childrens be $595 and parents pay for toddler childrens be $ 620 .

Option (A) is correct .

Step-by-step explanation:

Let us assume that the parents pay for primary childrens be x .

Let us assume that the parents pay for toddler childrens be y .

As given

.One location of The Smart Growing Preschool has 22 children in the primary class and 18 children in the toddler class.

The revenue at the first location is $24,250 .

Than the equation becomes

22x + 18y = 24250

As given

The other location has 30 children in the primary class and 15 children in the toddler class.

The revenue at the second location is $27150.

Than the equation becomes

30x + 15y = 27150

Than two equations are

22x + 18y = 24250

30x + 15y = 27150

Multiply 22x + 18y = 24250 by 15 .

15 × (22x + 18y = 24250)

15 × 22x + 15 × 18y = 15 × 24250

330x + 270y = 363750

Multiply 30x + 15y = 27150 by 18 .

18 × ( 30x + 15y = 27150 )

18 × 30x + 18 × 15y = 18 × 27150

540x + 270y = 488700

Now subtracted 330x + 270y = 363750 from 540x + 270y = 488700 .

540x - 330x + 270y - 270y = 488700 - 363750

210x = 124950

$x = \frac{124950}{210}$

x = $ 595

Putting in the equation

22x + 18y = 24250

22 × 595 + 18y = 24250

13090 + 18y = 24250

18y = 24250 - 13090

18y = 11160

$y = \frac{11160}{18}$

y = $ 620

Therefore the parents pay for primary childrens be $595 and parents pay for toddler childrens be $ 620 .

Option (A) is correct .

Answer from: Quest

I’ll you if you answer my questions!

Answer from: Quest

the length of o'p' is $1.5\times op$ .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

$k=\frac{o'p'}{op}$

the scale factor is 1.5.

$1.5=\frac{o'p'}{op}$

multiply both sides by op.

$1.5\times op=o'p'$

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is $1.5\times op$ .

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